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2/3y+2=1/5+y
We move all terms to the left:
2/3y+2-(1/5+y)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 5+y)!=0We add all the numbers together, and all the variables
We move all terms containing y to the left, all other terms to the right
y)!=-5
y!=-5/1
y!=-5
y∈R
2/3y-(+y+1/5)+2=0
We get rid of parentheses
2/3y-y+2-1/5=0
We calculate fractions
There is no solution for this equation
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