2/3y+4/y=1/3

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Solution for 2/3y+4/y=1/3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(2/3)*y+4/y = 1/3 // - 1/3

(2/3)*y+4/y-(1/3) = 0

(2/3)*y+4/y-1/3 = 0

2/3*y^1+4*y^-1-1/3*y^0 = 0

(2/3*y^2-1/3*y^1+4*y^0)/(y^1) = 0 // * y^2

y^1*(2/3*y^2-1/3*y^1+4*y^0) = 0

y^1

(2/3)*y^2+(-1/3)*y+4 = 0

(2/3)*y^2+(-1/3)*y+4 = 0

DELTA = (-1/3)^2-(4*4*(2/3))

DELTA = -95/9

DELTA < 0

y in { } 

y belongs to the empty set

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