2/3y+6=2/3(y

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Solution for 2/3y+6=2/3(y equation: 



2/3y+6=2/3(y

We move all terms to the left:

2/3y+6-(2/3(y)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R





Domain of the equation: 3y+6!=0

We move all terms containing y to the left, all other terms to the right

3y!=-6

y!=-6/3

y!=-2

y∈R



We calculate fractions


(6y+6)/(9y^2+6)+(-(2*3y)/(9y^2+6)=0



We calculate terms in parentheses: +(-(2*3y)/(9y^2+6), so:

-(2*3y)/(9y^2+6

We add all the numbers together, and all the variables

-(+2*3y)/(9y^2+6

We multiply all the terms by the denominator


-(+2*3y)

We get rid of parentheses

-2*3y

Wy multiply elements

-6y

Back to the equation:

+(-6y)



We get rid of parentheses

(6y+6)/(9y^2+6)-6y=0

We multiply all the terms by the denominator


(6y+6)-6y*(9y^2+6)=0

We multiply parentheses

-54y^3+(6y+6)-36y=0

We get rid of parentheses

-54y^3+6y-36y+6=0

We do not support eypression: y^3

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