2/3y+6=2/3(y+9

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Solution for 2/3y+6=2/3(y+9 equation: 



2/3y+6=2/3(y+9

We move all terms to the left:

2/3y+6-(2/3(y+9)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R





Domain of the equation: 3(y+9)+6!=0

We move all terms containing y to the left, all other terms to the right

3(y+9)!=-6

y∈R



We calculate fractions


(6y(y+6)/(9y^2(y+6)+(-(2*3y)/(9y^2(y+6)=0



We calculate terms in parentheses: +(6y(y+6)/(9y^2(y+6)+(-(2*3y)/(9y^2(y+6), so:

6y(y+6)/(9y^2(y+6)+(-(2*3y)/(9y^2(y+6

We can not solve this equation

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