2/3y+6=5(g-2)

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Solution for 2/3y+6=5(g-2) equation: 


x in (-oo:+oo)

(2/3)*y+6 = 5*(g-2) // - 5*(g-2)

(2/3)*y-(5*(g-2))+6 = 0

(2/3)*y-5*(g-2)+6 = 0

(2*y)/3-5*(g-2)+6 = 0

(-5*3*(g-2))/3+(2*y)/3+(3*6)/3 = 0

2*y-5*3*(g-2)+3*6 = 0

2*y-15*g+18+30 = 0

2*y-15*g+48 = 0

(2*y-15*g+48)/3 = 0

(2*y-15*g+48)/3 = 0 // * 3

2*y-15*g+48 = 0

x belongs to the empty set

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