2/3y+y-4=34

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Solution for 2/3y+y-4=34 equation:



2/3y+y-4=34
We move all terms to the left:
2/3y+y-4-(34)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
We add all the numbers together, and all the variables
y+2/3y-38=0
We multiply all the terms by the denominator
y*3y-38*3y+2=0
Wy multiply elements
3y^2-114y+2=0
a = 3; b = -114; c = +2;
Δ = b2-4ac
Δ = -1142-4·3·2
Δ = 12972
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12972}=\sqrt{4*3243}=\sqrt{4}*\sqrt{3243}=2\sqrt{3243}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-114)-2\sqrt{3243}}{2*3}=\frac{114-2\sqrt{3243}}{6} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-114)+2\sqrt{3243}}{2*3}=\frac{114+2\sqrt{3243}}{6} $

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