2/3y-4=7

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Solution for 2/3y-4=7 equation: 



2/3y-4=7

We move all terms to the left:

2/3y-4-(7)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

2/3y-11=0

We multiply all the terms by the denominator


-11*3y+2=0

Wy multiply elements

-33y+2=0

We move all terms containing y to the left, all other terms to the right

-33y=-2

y=-2/-33

y=2/33

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