2/3y=16/y+2

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Solution for 2/3y=16/y+2 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(2/3)*y = 16/y+2 // - 16/y+2

(2/3)*y-(16/y)-2 = 0

(2/3)*y-16*y^-1-2 = 0

2/3*y^1-16*y^-1-2*y^0 = 0

(2/3*y^2-2*y^1-16*y^0)/(y^1) = 0 // * y^2

y^1*(2/3*y^2-2*y^1-16*y^0) = 0

y^1

(2/3)*y^2-2*y-16 = 0

(2/3)*y^2-2*y-16 = 0

DELTA = (-2)^2-(-16*4*(2/3))

DELTA = 140/3

DELTA > 0

y = ((140/3)^(1/2)+2)/(2*(2/3)) or y = (2-(140/3)^(1/2))/(2*(2/3))

y = 3/4*((140/3)^(1/2)+2) or y = 3/4*(2-(140/3)^(1/2))

y in { 3/4*(2-(140/3)^(1/2)), 3/4*((140/3)^(1/2)+2)}

y in { 3/4*(2-(140/3)^(1/2)), 3/4*((140/3)^(1/2)+2) }

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