2/3z+11=13

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Solution for 2/3z+11=13 equation: 



2/3z+11=13

We move all terms to the left:

2/3z+11-(13)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We add all the numbers together, and all the variables

2/3z-2=0

We multiply all the terms by the denominator


-2*3z+2=0

Wy multiply elements

-6z+2=0

We move all terms containing z to the left, all other terms to the right

-6z=-2

z=-2/-6

z=1/3

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