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2/3z+1=1/3z
We move all terms to the left:
2/3z+1-(1/3z)=0
Domain of the equation: 3z!=0
z!=0/3
z!=0
z∈R
Domain of the equation: 3z)!=0We add all the numbers together, and all the variables
z!=0/1
z!=0
z∈R
2/3z-(+1/3z)+1=0
We get rid of parentheses
2/3z-1/3z+1=0
We multiply all the terms by the denominator
1*3z+2-1=0
We add all the numbers together, and all the variables
1*3z+1=0
Wy multiply elements
3z+1=0
We move all terms containing z to the left, all other terms to the right
3z=-1
z=-1/3
z=-1/3
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