2/3z+1=16

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Solution for 2/3z+1=16 equation: 



2/3z+1=16

We move all terms to the left:

2/3z+1-(16)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We add all the numbers together, and all the variables

2/3z-15=0

We multiply all the terms by the denominator


-15*3z+2=0

Wy multiply elements

-45z+2=0

We move all terms containing z to the left, all other terms to the right

-45z=-2

z=-2/-45

z=2/45

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