2/3z+9=-1/3z

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Solution for 2/3z+9=-1/3z equation: 



2/3z+9=-1/3z

We move all terms to the left:

2/3z+9-(-1/3z)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R





Domain of the equation: 3z)!=0

z!=0/1

z!=0

z∈R



We get rid of parentheses

2/3z+1/3z+9=0

We multiply all the terms by the denominator


9*3z+2+1=0

We add all the numbers together, and all the variables

9*3z+3=0

Wy multiply elements

27z+3=0

We move all terms containing z to the left, all other terms to the right

27z=-3

z=-3/27

z=-1/9

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