If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/3z=1/5
We move all terms to the left:
2/3z-(1/5)=0
Domain of the equation: 3z!=0We add all the numbers together, and all the variables
z!=0/3
z!=0
z∈R
2/3z-(+1/5)=0
We get rid of parentheses
2/3z-1/5=0
We calculate fractions
There is no solution for this equation
| -6x+14=50 | | y=-1/3-3-5 | | (2/3)x=-53 | | -7+6x=22-2x | | y/2+8=25 | | 2/3x=-53 | | -3y+13=-48 | | -19+(x÷3)=8 | | 7x/3-2=40 | | 8x-8=8(x-1) | | -6-y=-4 | | 4|2x-5|=8 | | 1/3(6x+12)=3x+4 | | -17=5+9(x-2) | | 3x+7/10=10 | | 7x-5-4x=1 | | 2x(5+x)=17 | | 3/4m=30 | | 6(x-3)=4x-5 | | 4(x+9)=4x+9 | | 8-3p=-8(1+8p) | | 5-6p=12-7p | | 6a=369 | | 1/2x+-4=-3-1/3x | | 26x+2=50+14x | | 2/5r=60 | | 2x+2(1-x)=4 | | 2x+0.3-x=3.3= | | F=(1/2)(r+6.5) | | -4x-16=3x+(-2) | | 3x(x+4)=18+x | | -6x-30=36-4x |