2/3z=17

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Solution for 2/3z=17 equation: 



2/3z=17

We move all terms to the left:

2/3z-(17)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We multiply all the terms by the denominator


-17*3z+2=0

Wy multiply elements

-51z+2=0

We move all terms containing z to the left, all other terms to the right

-51z=-2

z=-2/-51

z=2/51

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