2/3z=1=13

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Solution for 2/3z=1=13 equation:



2/3z=1=13
We move all terms to the left:
2/3z-(1)=0
Domain of the equation: 3z!=0
z!=0/3
z!=0
z∈R
We multiply all the terms by the denominator
-1*3z+2=0
Wy multiply elements
-3z+2=0
We move all terms containing z to the left, all other terms to the right
-3z=-2
z=-2/-3
z=2/3

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