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2/3z=4(1/9)
We move all terms to the left:
2/3z-(4(1/9))=0
Domain of the equation: 3z!=0We add all the numbers together, and all the variables
z!=0/3
z!=0
z∈R
2/3z-(4(+1/9))=0
We calculate fractions
()/27z^2+(-(4(+1*3z)/27z^2=0
We multiply all the terms by the denominator
(-(4(+1*3z)+()=0
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