2/42(9x+8)=3/7(2x+8)

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Solution for 2/42(9x+8)=3/7(2x+8) equation: 



2/42(9x+8)=3/7(2x+8)

We move all terms to the left:

2/42(9x+8)-(3/7(2x+8))=0



Domain of the equation: 42(9x+8)!=0

x∈R





Domain of the equation: 7(2x+8))!=0

x∈R



We calculate fractions


(14x2/(42(9x+8)*7(2x+8)))+(-126x9/(42(9x+8)*7(2x+8)))=0



We calculate terms in parentheses: +(14x2/(42(9x+8)*7(2x+8))), so:

14x2/(42(9x+8)*7(2x+8))

We multiply all the terms by the denominator


14x2

We add all the numbers together, and all the variables

14x^2

Back to the equation:

+(14x^2)





We calculate terms in parentheses: +(-126x9/(42(9x+8)*7(2x+8))), so:

-126x9/(42(9x+8)*7(2x+8))

We multiply all the terms by the denominator


-126x9

We add all the numbers together, and all the variables

-126x^9

We do not support expression: x^9

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