If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/4=12/4x
We move all terms to the left:
2/4-(12/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+12/4x)+2/4=0
We get rid of parentheses
-12/4x+2/4=0
We calculate fractions
=0
x=0/1
x=0
Równanie nie ma rozwiązania
| 6/3=10/x | | (12-3x)×=9(7x+18) | | −6(1+7k)=−2−7(1+6k) | | 2b+b-10=10+5b | | -2+6x+7x=37 | | x3+3=24 | | 2y-18=-24+12 | | -0.25z=(-1.25) | | 14g+6g−23=g | | 29=-d+6 | | 4x+7=-7x+5 | | -8.5x-3.5x=-75 | | -5(8+r)+6(r+6)=8r-5r | | -2x+6=4.5 | | 10-5m=-10-9m | | 2x-30=180-x | | 2/3l=22 | | -26=6n+4 | | 5h-10=2+7h | | 23xX=100 | | 25^x=10^7 | | F(4)=2x+5 | | 3y-4=6‐2y | | z+3z-2=0 | | 2q=-6+q | | 256x-100=412 | | F(x)=4x+4/3x+11 | | 2(3.14)(3)=x | | (a+7)∙8–3a= | | 2/3l=32 | | 5(4x-1)=-3(1-2x) | | 8-4t=3t |