2/4=x2

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Solution for 2/4=x2 equation:



2/4=x2
We move all terms to the left:
2/4-(x2)=0
We add all the numbers together, and all the variables
-1x^2+2/4=0
We multiply all the terms by the denominator
-1x^2*4+2=0
Wy multiply elements
-4x^2+2=0
a = -4; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-4)·2
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{2}}{2*-4}=\frac{0-4\sqrt{2}}{-8} =-\frac{4\sqrt{2}}{-8} =-\frac{\sqrt{2}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{2}}{2*-4}=\frac{0+4\sqrt{2}}{-8} =\frac{4\sqrt{2}}{-8} =\frac{\sqrt{2}}{-2} $

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