2/4h-1/3h+11=8

Solution for 2/4h-1/3h+11=8 equation:

2/4h-1/3h+11=8

We move all terms to the left:

2/4h-1/3h+11-(8)=0


Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R



Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R


We add all the numbers together, and all the variables

2/4h-1/3h+3=0

We calculate fractions


6h/12h^2+(-4h)/12h^2+3=0

We multiply all the terms by the denominator


6h+(-4h)+3*12h^2=0

Wy multiply elements

36h^2+6h+(-4h)=0

We get rid of parentheses

36h^2+6h-4h=0

We add all the numbers together, and all the variables

36h^2+2h=0

a = 36; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·36·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*36}=\frac{-4}{72}
=-1/18
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*36}=\frac{0}{72}
=0
$