2/4t-3/5t=26

Solution for 2/4t-3/5t=26 equation:

2/4t-3/5t=26

We move all terms to the left:

2/4t-3/5t-(26)=0


Domain of the equation: 4t!=0

t!=0/4

t!=0

t∈R



Domain of the equation: 5t!=0

t!=0/5

t!=0

t∈R


We calculate fractions


10t/20t^2+(-12t)/20t^2-26=0

We multiply all the terms by the denominator


10t+(-12t)-26*20t^2=0

Wy multiply elements

-520t^2+10t+(-12t)=0

We get rid of parentheses

-520t^2+10t-12t=0

We add all the numbers together, and all the variables

-520t^2-2t=0

a = -520; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-520)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-520}=\frac{0}{-1040}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-520}=\frac{4}{-1040}
=-1/260
$