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2/4x+4=1/2x+1
We move all terms to the left:
2/4x+4-(1/2x+1)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+1)!=0We get rid of parentheses
x∈R
2/4x-1/2x-1+4=0
We calculate fractions
4x/8x^2+(-4x)/8x^2-1+4=0
We add all the numbers together, and all the variables
4x/8x^2+(-4x)/8x^2+3=0
We multiply all the terms by the denominator
4x+(-4x)+3*8x^2=0
Wy multiply elements
24x^2+4x+(-4x)=0
We get rid of parentheses
24x^2+4x-4x=0
We add all the numbers together, and all the variables
24x^2=0
a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{48}=0$
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