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2/4x+5-1/2x=3
We move all terms to the left:
2/4x+5-1/2x-(3)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2/4x-1/2x+2=0
We calculate fractions
4x/8x^2+(-4x)/8x^2+2=0
We multiply all the terms by the denominator
4x+(-4x)+2*8x^2=0
Wy multiply elements
16x^2+4x+(-4x)=0
We get rid of parentheses
16x^2+4x-4x=0
We add all the numbers together, and all the variables
16x^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{32}=0$
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