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2/4x-1/2=5+3/8x
We move all terms to the left:
2/4x-1/2-(5+3/8x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/4x-(3/8x+5)-1/2=0
We get rid of parentheses
2/4x-3/8x-5-1/2=0
We calculate fractions
(-256x^2)/128x^2+64x/128x^2+(-48x)/128x^2-5=0
We multiply all the terms by the denominator
(-256x^2)+64x+(-48x)-5*128x^2=0
Wy multiply elements
(-256x^2)-640x^2+64x+(-48x)=0
We get rid of parentheses
-256x^2-640x^2+64x-48x=0
We add all the numbers together, and all the variables
-896x^2+16x=0
a = -896; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-896)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-896}=\frac{-32}{-1792} =1/56 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-896}=\frac{0}{-1792} =0 $
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