2/4z-7=35

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Solution for 2/4z-7=35 equation: 



2/4z-7=35

We move all terms to the left:

2/4z-7-(35)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

2/4z-42=0

We multiply all the terms by the denominator


-42*4z+2=0

Wy multiply elements

-168z+2=0

We move all terms containing z to the left, all other terms to the right

-168z=-2

z=-2/-168

z=1/84

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