2/4z=4(1/4)

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Solution for 2/4z=4(1/4) equation:



2/4z=4(1/4)
We move all terms to the left:
2/4z-(4(1/4))=0
Domain of the equation: 4z!=0
z!=0/4
z!=0
z∈R
We add all the numbers together, and all the variables
2/4z-(4(+1/4))=0
We calculate fractions
()/16z^2+(-(4(+1*4z)/16z^2=0
We multiply all the terms by the denominator
(-(4(+1*4z)+()=0
We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
-(4(+1*4z)+(
We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
-(4(+1*4z)+(
We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
-(4(+1*4z)+(
We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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We calculate terms in parentheses: +(-(4(+1*4z)+(), so:
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