2/5(-30y-20)=-32

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Solution for 2/5(-30y-20)=-32 equation:



2/5(-30y-20)=-32
We move all terms to the left:
2/5(-30y-20)-(-32)=0
Domain of the equation: 5(-30y-20)!=0
y∈R
We add all the numbers together, and all the variables
2/5(-30y-20)+32=0
We multiply all the terms by the denominator
32*5(-30y-20)+2=0
Wy multiply elements
160y(-+2=0
We use the square of the difference formula
160y(-2=0

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