2/5(-4+1b)=b/5

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Solution for 2/5(-4+1b)=b/5 equation: 


b in (-oo:+oo)

(2/5)*(1*b-4) = b/5 // - b/5

(2/5)*(1*b-4)-(b/5) = 0

(2/5)*(b-4)-(b/5) = 0

2/5*(b-4)-b/5 = 0

(2/5*5*(b-4))/5-b/5 = 0

2/5*5*(b-4)-b = 0

b-8 = 0

(b-8)/5 = 0

(b-8)/5 = 0 // * 5

b-8 = 0

b-8 = 0 // + 8

b = 8

b = 8

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