2/5(10t-50)=6-2t

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Solution for 2/5(10t-50)=6-2t equation: 



2/5(10t-50)=6-2t

We move all terms to the left:

2/5(10t-50)-(6-2t)=0



Domain of the equation: 5(10t-50)!=0

t∈R



We add all the numbers together, and all the variables

2/5(10t-50)-(-2t+6)=0

We get rid of parentheses

2/5(10t-50)+2t-6=0

We multiply all the terms by the denominator


2t*5(10t-50)-6*5(10t-50)+2=0

Wy multiply elements

10t^2(1-30t(1+2=0

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