2/5(10x)+5=21

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Solution for 2/5(10x)+5=21 equation: 



2/5(10x)+5=21

We move all terms to the left:

2/5(10x)+5-(21)=0



Domain of the equation: 510x!=0

x!=0/510

x!=0

x∈R



We add all the numbers together, and all the variables

2/510x-16=0

We multiply all the terms by the denominator


-16*510x+2=0

Wy multiply elements

-8160x+2=0

We move all terms containing x to the left, all other terms to the right

-8160x=-2

x=-2/-8160

x=1/4080

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