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(2/5)*(10*x+15) = 4*x-4 // - 4*x-4
(2/5)*(10*x+15)-(4*x)+4 = 0
(2/5)*(10*x+15)-4*x+4 = 0
2/5*(10*x+15)-4*x+4 = 0
2/5*(10*x+15)-4*x+4 = 0
4+6 = 0
10 = 0
10 = 0
x belongs to the empty set
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