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2/5(10x-3)+x=9/5
We move all terms to the left:
2/5(10x-3)+x-(9/5)=0
Domain of the equation: 5(10x-3)!=0We add all the numbers together, and all the variables
x∈R
2/5(10x-3)+x-(+9/5)=0
We add all the numbers together, and all the variables
x+2/5(10x-3)-(+9/5)=0
We get rid of parentheses
x+2/5(10x-3)-9/5=0
We calculate fractions
x=0
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