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2/5(15x-30)+2x=-4(-2x)-12
We move all terms to the left:
2/5(15x-30)+2x-(-4(-2x)-12)=0
Domain of the equation: 5(15x-30)!=0We add all the numbers together, and all the variables
x∈R
2x+2/5(15x-30)-(-4(-2x)-12)=0
We multiply all the terms by the denominator
2x*5(15x-30)-((-4(-2x)-12))*5(15x-30)+2=0
We calculate terms in parentheses: -((-4(-2x)-12))*5(15x-30), so:Wy multiply elements
(-4(-2x)-12))*5(15x-30
10x^2(1-((-4(-2x)-12))*5(15x-30)+2=0
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