2/5(20x-35)=75

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Solution for 2/5(20x-35)=75 equation: 



2/5(20x-35)=75

We move all terms to the left:

2/5(20x-35)-(75)=0



Domain of the equation: 5(20x-35)!=0

x∈R



We multiply all the terms by the denominator


-75*5(20x-35)+2=0

Wy multiply elements

-375x(2+2=0

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