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2/5(25x+35)-11=2/3(9x-24)
We move all terms to the left:
2/5(25x+35)-11-(2/3(9x-24))=0
Domain of the equation: 5(25x+35)!=0
x∈R
Domain of the equation: 3(9x-24))!=0We calculate fractions
x∈R
(6x9/(5(25x+35)*3(9x-24)))+(-10x2/(5(25x+35)*3(9x-24)))-11=0
We calculate terms in parentheses: +(6x9/(5(25x+35)*3(9x-24))), so:
6x9/(5(25x+35)*3(9x-24))
We multiply all the terms by the denominator
6x9
We add all the numbers together, and all the variables
6x^9
We do not support expression: x^9
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