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2/5(26-5x)-7/3x=1/3(52-17x)
We move all terms to the left:
2/5(26-5x)-7/3x-(1/3(52-17x))=0
Domain of the equation: 5(26-5x)!=0
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3(52-17x))!=0We add all the numbers together, and all the variables
x∈R
2/5(-5x+26)-7/3x-(1/3(-17x+52))=0
We calculate fractions
-105x^2(-)/(5(-5x+26)*3x*3(-17x+52)))+(+54x^2/(5(-5x+26)*3x*3(-17x+52)))+(-(1*5(-5x+26)*3x)/(5(-5x+26)*3x*3(-17x+52)))=0
We calculate terms in parentheses: -(1*5(-5x+26)*3x)/(5(-5x+26)*3x*3(-17x+52))), so:We add all the numbers together, and all the variables
1*5(-5x+26)*3x)/(5(-5x+26)*3x*3(-17x+52))
We multiply all the terms by the denominator
1*5(-5x+26)*3x)
Wy multiply elements
15x^2(-
Back to the equation:
-(15x^2(-)
-105x^20/(5(-5x+26)*3x*3(-17x+52)))+(+54x^2/(5(-5x+26)*3x*3(-17x+52)))+(-(15x^20=0
We multiply all the terms by the denominator
-105x^20+54x^2-(15x^20*(5(-5x+26)*3x*3(-17x+52)))+(=0
We calculate terms in parentheses: -(15x^20*(5(-5x+26)*3x*3(-17x+52))), so:
15x^20*(5(-5x+26)*3x*3(-17x+52))
We do not support expression: x^20
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