2/5(2d-4)=3(d+2)-4/5d

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Solution for 2/5(2d-4)=3(d+2)-4/5d equation: 



2/5(2d-4)=3(d+2)-4/5d

We move all terms to the left:

2/5(2d-4)-(3(d+2)-4/5d)=0



Domain of the equation: 5(2d-4)!=0

d∈R





Domain of the equation: 5d)!=0

d!=0/1

d!=0

d∈R



We calculate fractions


10d/(-100d^2+10d)+(-(3d-20d2)/(-100d^2+10d)=0



We calculate terms in parentheses: +(-(3d-20d2)/(-100d^2+10d), so:

-(3d-20d2)/(-100d^2+10d

We add all the numbers together, and all the variables

-(+3d-20d^2)/(-100d^2+10d

We multiply all the terms by the denominator


-(+3d-20d^2)

We get rid of parentheses

20d^2-3d

Back to the equation:

+(20d^2-3d)



We get rid of parentheses

10d/(-100d^2+10d)+20d^2-3d=0

We multiply all the terms by the denominator


20d^2*(-100d^2+10d)-3d*(-100d^2+10d)+10d=0

We multiply parentheses

20d^2*(-100d^2+10d)+300d^3-30d^2+10d=0

We do not support edpression: d^3

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