2/5(2k+35)-8=12

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Solution for 2/5(2k+35)-8=12 equation: 



2/5(2k+35)-8=12

We move all terms to the left:

2/5(2k+35)-8-(12)=0



Domain of the equation: 5(2k+35)!=0

k∈R



We add all the numbers together, and all the variables

2/5(2k+35)-20=0

We multiply all the terms by the denominator


-20*5(2k+35)+2=0

Wy multiply elements

-100k(2+2=0

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