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2/5(2x+3)=4(2-3x)+6
We move all terms to the left:
2/5(2x+3)-(4(2-3x)+6)=0
Domain of the equation: 5(2x+3)!=0We add all the numbers together, and all the variables
x∈R
2/5(2x+3)-(4(-3x+2)+6)=0
We multiply all the terms by the denominator
-((4(-3x+2)+6))*5(2x+3)+2=0
We calculate terms in parentheses: -((4(-3x+2)+6))*5(2x+3), so:
(4(-3x+2)+6))*5(2x+3
We calculate terms in parentheses: -((4(-3x+2)+6))*5(2x+3), so:
(4(-3x+2)+6))*5(2x+3
We calculate terms in parentheses: -((4(-3x+2)+6))*5(2x+3), so:
(4(-3x+2)+6))*5(2x+3
We calculate terms in parentheses: -((4(-3x+2)+6))*5(2x+3), so:
(4(-3x+2)+6))*5(2x+3
We calculate terms in parentheses: -((4(-3x+2)+6))*5(2x+3), so:
(4(-3x+2)+6))*5(2x+3
We calculate terms in parentheses: -((4(-3x+2)+6))*5(2x+3), so:
(4(-3x+2)+6))*5(2x+3
We calculate terms in parentheses: -((4(-3x+2)+6))*5(2x+3), so:
(4(-3x+2)+6))*5(2x+3
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(4(-3x+2)+6))*5(2x+3
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(4(-3x+2)+6))*5(2x+3
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We calculate
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