2/5(3k+5)-1/3(5k-2)=k+3/5

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Solution for 2/5(3k+5)-1/3(5k-2)=k+3/5 equation: 


k in (-oo:+oo)

(2/5)*(3*k+5)-((1/3)*(5*k-2)) = k+3/5 // - k+3/5

(2/5)*(3*k+5)-((1/3)*(5*k-2))-k-(3/5) = 0

(2/5)*(3*k+5)+(-1/3)*(5*k-2)-k-3/5 = 0

2/5*(3*k+5)-1/3*(5*k-2)-k-3/5 = 0

(2/5*5*(3*k+5))/5+(-1/3*5*(5*k-2))/5+(5*(-k))/5-3/5 = 0

2/5*5*(3*k+5)-1/3*5*(5*k-2)+5*(-k)-3 = 0

40/3-7/3*k-5*k-3 = 0

40/3-22/3*k-3 = 0

31/3-22/3*k = 0

(31/3-22/3*k)/5 = 0

(31/3-22/3*k)/5 = 0 // * 5

31/3-22/3*k = 0

31/3-22/3*k = 0 // - 31/3

-22/3*k = -31/3 // : -22/3

k = -31/3/(-22/3)

k = 31/22

k = 31/22

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