2/5(3x+1)=16

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Solution for 2/5(3x+1)=16 equation: 



2/5(3x+1)=16

We move all terms to the left:

2/5(3x+1)-(16)=0



Domain of the equation: 5(3x+1)!=0

x∈R



We multiply all the terms by the denominator


-16*5(3x+1)+2=0

Wy multiply elements

-80x(3+2=0

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