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2/5(3x+40)+3/4(12-x)=2x-37
We move all terms to the left:
2/5(3x+40)+3/4(12-x)-(2x-37)=0
Domain of the equation: 5(3x+40)!=0
x∈R
Domain of the equation: 4(12-x)!=0We add all the numbers together, and all the variables
x∈R
2/5(3x+40)+3/4(-1x+12)-(2x-37)=0
We get rid of parentheses
2/5(3x+40)+3/4(-1x+12)-2x+37=0
We calculate fractions
-2x+(8x(-)/(5(3x+40)*4(-1x+12))+(15x3/(5(3x+40)*4(-1x+12))+37=0
We can not solve this equation
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