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(2/5)*(3*x-7)*(5*x+10) = 0
2/5*(3*x-7)*(5*x+10) = 0
( 3*x-7 )
3*x-7 = 0 // + 7
3*x = 7 // : 3
x = 7/3
( 5*x+10 )
5*x+10 = 0 // - 10
5*x = -10 // : 5
x = -10/5
x = -2
x in { 7/3, -2 }
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