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2/5(4x-2)-1=2/5(x-3)
We move all terms to the left:
2/5(4x-2)-1-(2/5(x-3))=0
Domain of the equation: 5(4x-2)!=0
x∈R
Domain of the equation: 5(x-3))!=0We calculate fractions
x∈R
(10xx/(5(4x-2)*5(x-3)))+(-10x4/(5(4x-2)*5(x-3)))-1=0
We calculate terms in parentheses: +(10xx/(5(4x-2)*5(x-3))), so:
10xx/(5(4x-2)*5(x-3))
We multiply all the terms by the denominator
10xx
Back to the equation:
+(10xx)
We calculate terms in parentheses: +(-10x4/(5(4x-2)*5(x-3))), so:
-10x4/(5(4x-2)*5(x-3))
We multiply all the terms by the denominator
-10x4
We add all the numbers together, and all the variables
-10x^4
We do not support expression: x^4
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