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2/5(4x-3)-2=4/5-x
We move all terms to the left:
2/5(4x-3)-2-(4/5-x)=0
Domain of the equation: 5(4x-3)!=0
x∈R
Domain of the equation: 5-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)!=-5
x!=-5/1
x!=-5
x∈R
2/5(4x-3)-(-1x+4/5)-2=0
We get rid of parentheses
2/5(4x-3)+1x-2-4/5=0
We calculate fractions
1x-2=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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