2/5(5b+10)=15

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Solution for 2/5(5b+10)=15 equation: 



2/5(5b+10)=15

We move all terms to the left:

2/5(5b+10)-(15)=0



Domain of the equation: 5(5b+10)!=0

b∈R



We multiply all the terms by the denominator


-15*5(5b+10)+2=0

Wy multiply elements

-75b(5+2=0

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