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2/5(5x+2)=x
We move all terms to the left:
2/5(5x+2)-(x)=0
Domain of the equation: 5(5x+2)!=0We add all the numbers together, and all the variables
x∈R
-1x+2/5(5x+2)=0
We multiply all the terms by the denominator
-1x*5(5x+2)+2=0
Wy multiply elements
-5x^2(5+2=0
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