2/5(5x+20)=1/2(6x+28)

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Solution for 2/5(5x+20)=1/2(6x+28) equation:



2/5(5x+20)=1/2(6x+28)
We move all terms to the left:
2/5(5x+20)-(1/2(6x+28))=0
Domain of the equation: 5(5x+20)!=0
x∈R
Domain of the equation: 2(6x+28))!=0
x∈R
We calculate fractions
(4x6/(5(5x+20)*2(6x+28)))+(-5x5/(5(5x+20)*2(6x+28)))=0
We calculate terms in parentheses: +(4x6/(5(5x+20)*2(6x+28))), so:
4x6/(5(5x+20)*2(6x+28))
We multiply all the terms by the denominator
4x6
We add all the numbers together, and all the variables
4x^6
We do not support expression: x^6

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