2/5(6x-2)=1/5(10x+3)

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Solution for 2/5(6x-2)=1/5(10x+3) equation: 



2/5(6x-2)=1/5(10x+3)

We move all terms to the left:

2/5(6x-2)-(1/5(10x+3))=0



Domain of the equation: 5(6x-2)!=0

x∈R





Domain of the equation: 5(10x+3))!=0

x∈R



We calculate fractions


(10x1/(5(6x-2)*5(10x+3)))+(-5x6/(5(6x-2)*5(10x+3)))=0



We calculate terms in parentheses: +(10x1/(5(6x-2)*5(10x+3))), so:

10x1/(5(6x-2)*5(10x+3))

We multiply all the terms by the denominator


10x1

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)





We calculate terms in parentheses: +(-5x6/(5(6x-2)*5(10x+3))), so:

-5x6/(5(6x-2)*5(10x+3))

We multiply all the terms by the denominator


-5x6

We add all the numbers together, and all the variables

-5x^6

We do not support expression: x^6

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