2/5(6y-4)+8=10

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Solution for 2/5(6y-4)+8=10 equation: 



2/5(6y-4)+8=10

We move all terms to the left:

2/5(6y-4)+8-(10)=0



Domain of the equation: 5(6y-4)!=0

y∈R



We add all the numbers together, and all the variables

2/5(6y-4)-2=0

We multiply all the terms by the denominator


-2*5(6y-4)+2=0

Wy multiply elements

-10y(6+2=0

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